import functools
import numpy as np
import math
import types
import warnings

# trapz is a public function for scipy.integrate,
# even though it's actually a NumPy function.
from numpy import trapz
from scipy.special import roots_legendre
from scipy.special import gammaln

__all__ = ['fixed_quad', 'quadrature', 'romberg', 'trapz', 'simps', 'romb',
           'cumtrapz', 'newton_cotes', 'AccuracyWarning']


# Make See Also linking for our local copy work properly
def _copy_func(f):
    """Based on http://stackoverflow.com/a/6528148/190597 (Glenn Maynard)"""
    g = types.FunctionType(f.__code__, f.__globals__, name=f.__name__,
                           argdefs=f.__defaults__, closure=f.__closure__)
    g = functools.update_wrapper(g, f)
    g.__kwdefaults__ = f.__kwdefaults__
    return g


trapz = _copy_func(trapz)
if trapz.__doc__:
    trapz.__doc__ = trapz.__doc__.replace('sum, cumsum', 'numpy.cumsum')


class AccuracyWarning(Warning):
    pass


def _cached_roots_legendre(n):
    """
    Cache roots_legendre results to speed up calls of the fixed_quad
    function.
    """
    if n in _cached_roots_legendre.cache:
        return _cached_roots_legendre.cache[n]

    _cached_roots_legendre.cache[n] = roots_legendre(n)
    return _cached_roots_legendre.cache[n]


_cached_roots_legendre.cache = dict()


def fixed_quad(func, a, b, args=(), n=5):
    """
    Compute a definite integral using fixed-order Gaussian quadrature.

    Integrate `func` from `a` to `b` using Gaussian quadrature of
    order `n`.

    Parameters
    ----------
    func : callable
        A Python function or method to integrate (must accept vector inputs).
        If integrating a vector-valued function, the returned array must have
        shape ``(..., len(x))``.
    a : float
        Lower limit of integration.
    b : float
        Upper limit of integration.
    args : tuple, optional
        Extra arguments to pass to function, if any.
    n : int, optional
        Order of quadrature integration. Default is 5.

    Returns
    -------
    val : float
        Gaussian quadrature approximation to the integral
    none : None
        Statically returned value of None


    See Also
    --------
    quad : adaptive quadrature using QUADPACK
    dblquad : double integrals
    tplquad : triple integrals
    romberg : adaptive Romberg quadrature
    quadrature : adaptive Gaussian quadrature
    romb : integrators for sampled data
    simps : integrators for sampled data
    cumtrapz : cumulative integration for sampled data
    ode : ODE integrator
    odeint : ODE integrator

    Examples
    --------
    >>> from scipy import integrate
    >>> f = lambda x: x**8
    >>> integrate.fixed_quad(f, 0.0, 1.0, n=4)
    (0.1110884353741496, None)
    >>> integrate.fixed_quad(f, 0.0, 1.0, n=5)
    (0.11111111111111102, None)
    >>> print(1/9.0)  # analytical result
    0.1111111111111111

    >>> integrate.fixed_quad(np.cos, 0.0, np.pi/2, n=4)
    (0.9999999771971152, None)
    >>> integrate.fixed_quad(np.cos, 0.0, np.pi/2, n=5)
    (1.000000000039565, None)
    >>> np.sin(np.pi/2)-np.sin(0)  # analytical result
    1.0

    """
    x, w = _cached_roots_legendre(n)
    x = np.real(x)
    if np.isinf(a) or np.isinf(b):
        raise ValueError("Gaussian quadrature is only available for "
                         "finite limits.")
    y = (b-a)*(x+1)/2.0 + a
    return (b-a)/2.0 * np.sum(w*func(y, *args), axis=-1), None


def vectorize1(func, args=(), vec_func=False):
    """Vectorize the call to a function.

    This is an internal utility function used by `romberg` and
    `quadrature` to create a vectorized version of a function.

    If `vec_func` is True, the function `func` is assumed to take vector
    arguments.

    Parameters
    ----------
    func : callable
        User defined function.
    args : tuple, optional
        Extra arguments for the function.
    vec_func : bool, optional
        True if the function func takes vector arguments.

    Returns
    -------
    vfunc : callable
        A function that will take a vector argument and return the
        result.

    """
    if vec_func:
        def vfunc(x):
            return func(x, *args)
    else:
        def vfunc(x):
            if np.isscalar(x):
                return func(x, *args)
            x = np.asarray(x)
            # call with first point to get output type
            y0 = func(x[0], *args)
            n = len(x)
            dtype = getattr(y0, 'dtype', type(y0))
            output = np.empty((n,), dtype=dtype)
            output[0] = y0
            for i in range(1, n):
                output[i] = func(x[i], *args)
            return output
    return vfunc


def quadrature(func, a, b, args=(), tol=1.49e-8, rtol=1.49e-8, maxiter=50,
               vec_func=True, miniter=1):
    """
    Compute a definite integral using fixed-tolerance Gaussian quadrature.

    Integrate `func` from `a` to `b` using Gaussian quadrature
    with absolute tolerance `tol`.

    Parameters
    ----------
    func : function
        A Python function or method to integrate.
    a : float
        Lower limit of integration.
    b : float
        Upper limit of integration.
    args : tuple, optional
        Extra arguments to pass to function.
    tol, rtol : float, optional
        Iteration stops when error between last two iterates is less than
        `tol` OR the relative change is less than `rtol`.
    maxiter : int, optional
        Maximum order of Gaussian quadrature.
    vec_func : bool, optional
        True or False if func handles arrays as arguments (is
        a "vector" function). Default is True.
    miniter : int, optional
        Minimum order of Gaussian quadrature.

    Returns
    -------
    val : float
        Gaussian quadrature approximation (within tolerance) to integral.
    err : float
        Difference between last two estimates of the integral.

    See also
    --------
    romberg: adaptive Romberg quadrature
    fixed_quad: fixed-order Gaussian quadrature
    quad: adaptive quadrature using QUADPACK
    dblquad: double integrals
    tplquad: triple integrals
    romb: integrator for sampled data
    simps: integrator for sampled data
    cumtrapz: cumulative integration for sampled data
    ode: ODE integrator
    odeint: ODE integrator

    Examples
    --------
    >>> from scipy import integrate
    >>> f = lambda x: x**8
    >>> integrate.quadrature(f, 0.0, 1.0)
    (0.11111111111111106, 4.163336342344337e-17)
    >>> print(1/9.0)  # analytical result
    0.1111111111111111

    >>> integrate.quadrature(np.cos, 0.0, np.pi/2)
    (0.9999999999999536, 3.9611425250996035e-11)
    >>> np.sin(np.pi/2)-np.sin(0)  # analytical result
    1.0

    """
    if not isinstance(args, tuple):
        args = (args,)
    vfunc = vectorize1(func, args, vec_func=vec_func)
    val = np.inf
    err = np.inf
    maxiter = max(miniter+1, maxiter)
    for n in range(miniter, maxiter+1):
        newval = fixed_quad(vfunc, a, b, (), n)[0]
        err = abs(newval-val)
        val = newval

        if err < tol or err < rtol*abs(val):
            break
    else:
        warnings.warn(
            "maxiter (%d) exceeded. Latest difference = %e" % (maxiter, err),
            AccuracyWarning)
    return val, err


def tupleset(t, i, value):
    l = list(t)
    l[i] = value
    return tuple(l)


def cumtrapz(y, x=None, dx=1.0, axis=-1, initial=None):
    """
    Cumulatively integrate y(x) using the composite trapezoidal rule.

    Parameters
    ----------
    y : array_like
        Values to integrate.
    x : array_like, optional
        The coordinate to integrate along. If None (default), use spacing `dx`
        between consecutive elements in `y`.
    dx : float, optional
        Spacing between elements of `y`. Only used if `x` is None.
    axis : int, optional
        Specifies the axis to cumulate. Default is -1 (last axis).
    initial : scalar, optional
        If given, insert this value at the beginning of the returned result.
        Typically this value should be 0. Default is None, which means no
        value at ``x[0]`` is returned and `res` has one element less than `y`
        along the axis of integration.

    Returns
    -------
    res : ndarray
        The result of cumulative integration of `y` along `axis`.
        If `initial` is None, the shape is such that the axis of integration
        has one less value than `y`. If `initial` is given, the shape is equal
        to that of `y`.

    See Also
    --------
    numpy.cumsum, numpy.cumprod
    quad: adaptive quadrature using QUADPACK
    romberg: adaptive Romberg quadrature
    quadrature: adaptive Gaussian quadrature
    fixed_quad: fixed-order Gaussian quadrature
    dblquad: double integrals
    tplquad: triple integrals
    romb: integrators for sampled data
    ode: ODE integrators
    odeint: ODE integrators

    Examples
    --------
    >>> from scipy import integrate
    >>> import matplotlib.pyplot as plt

    >>> x = np.linspace(-2, 2, num=20)
    >>> y = x
    >>> y_int = integrate.cumtrapz(y, x, initial=0)
    >>> plt.plot(x, y_int, 'ro', x, y[0] + 0.5 * x**2, 'b-')
    >>> plt.show()

    """
    y = np.asarray(y)
    if x is None:
        d = dx
    else:
        x = np.asarray(x)
        if x.ndim == 1:
            d = np.diff(x)
            # reshape to correct shape
            shape = [1] * y.ndim
            shape[axis] = -1
            d = d.reshape(shape)
        elif len(x.shape) != len(y.shape):
            raise ValueError("If given, shape of x must be 1-D or the "
                             "same as y.")
        else:
            d = np.diff(x, axis=axis)

        if d.shape[axis] != y.shape[axis] - 1:
            raise ValueError("If given, length of x along axis must be the "
                             "same as y.")

    nd = len(y.shape)
    slice1 = tupleset((slice(None),)*nd, axis, slice(1, None))
    slice2 = tupleset((slice(None),)*nd, axis, slice(None, -1))
    res = np.cumsum(d * (y[slice1] + y[slice2]) / 2.0, axis=axis)

    if initial is not None:
        if not np.isscalar(initial):
            raise ValueError("`initial` parameter should be a scalar.")

        shape = list(res.shape)
        shape[axis] = 1
        res = np.concatenate([np.full(shape, initial, dtype=res.dtype), res],
                             axis=axis)

    return res


def _basic_simps(y, start, stop, x, dx, axis):
    nd = len(y.shape)
    if start is None:
        start = 0
    step = 2
    slice_all = (slice(None),)*nd
    slice0 = tupleset(slice_all, axis, slice(start, stop, step))
    slice1 = tupleset(slice_all, axis, slice(start+1, stop+1, step))
    slice2 = tupleset(slice_all, axis, slice(start+2, stop+2, step))

    if x is None:  # Even-spaced Simpson's rule.
        result = np.sum(dx/3.0 * (y[slice0]+4*y[slice1]+y[slice2]),
                        axis=axis)
    else:
        # Account for possibly different spacings.
        #    Simpson's rule changes a bit.
        h = np.diff(x, axis=axis)
        sl0 = tupleset(slice_all, axis, slice(start, stop, step))
        sl1 = tupleset(slice_all, axis, slice(start+1, stop+1, step))
        h0 = h[sl0]
        h1 = h[sl1]
        hsum = h0 + h1
        hprod = h0 * h1
        h0divh1 = h0 / h1
        tmp = hsum/6.0 * (y[slice0]*(2-1.0/h0divh1) +
                          y[slice1]*hsum*hsum/hprod +
                          y[slice2]*(2-h0divh1))
        result = np.sum(tmp, axis=axis)
    return result


def simps(y, x=None, dx=1, axis=-1, even='avg'):
    """
    Integrate y(x) using samples along the given axis and the composite
    Simpson's rule. If x is None, spacing of dx is assumed.

    If there are an even number of samples, N, then there are an odd
    number of intervals (N-1), but Simpson's rule requires an even number
    of intervals. The parameter 'even' controls how this is handled.

    Parameters
    ----------
    y : array_like
        Array to be integrated.
    x : array_like, optional
        If given, the points at which `y` is sampled.
    dx : int, optional
        Spacing of integration points along axis of `x`. Only used when
        `x` is None. Default is 1.
    axis : int, optional
        Axis along which to integrate. Default is the last axis.
    even : str {'avg', 'first', 'last'}, optional
        'avg' : Average two results:1) use the first N-2 intervals with
                  a trapezoidal rule on the last interval and 2) use the last
                  N-2 intervals with a trapezoidal rule on the first interval.

        'first' : Use Simpson's rule for the first N-2 intervals with
                a trapezoidal rule on the last interval.

        'last' : Use Simpson's rule for the last N-2 intervals with a
               trapezoidal rule on the first interval.

    See Also
    --------
    quad: adaptive quadrature using QUADPACK
    romberg: adaptive Romberg quadrature
    quadrature: adaptive Gaussian quadrature
    fixed_quad: fixed-order Gaussian quadrature
    dblquad: double integrals
    tplquad: triple integrals
    romb: integrators for sampled data
    cumtrapz: cumulative integration for sampled data
    ode: ODE integrators
    odeint: ODE integrators

    Notes
    -----
    For an odd number of samples that are equally spaced the result is
    exact if the function is a polynomial of order 3 or less. If
    the samples are not equally spaced, then the result is exact only
    if the function is a polynomial of order 2 or less.

    Examples
    --------
    >>> from scipy import integrate
    >>> x = np.arange(0, 10)
    >>> y = np.arange(0, 10)

    >>> integrate.simps(y, x)
    40.5

    >>> y = np.power(x, 3)
    >>> integrate.simps(y, x)
    1642.5
    >>> integrate.quad(lambda x: x**3, 0, 9)[0]
    1640.25

    >>> integrate.simps(y, x, even='first')
    1644.5

    """
    y = np.asarray(y)
    nd = len(y.shape)
    N = y.shape[axis]
    last_dx = dx
    first_dx = dx
    returnshape = 0
    if x is not None:
        x = np.asarray(x)
        if len(x.shape) == 1:
            shapex = [1] * nd
            shapex[axis] = x.shape[0]
            saveshape = x.shape
            returnshape = 1
            x = x.reshape(tuple(shapex))
        elif len(x.shape) != len(y.shape):
            raise ValueError("If given, shape of x must be 1-D or the "
                             "same as y.")
        if x.shape[axis] != N:
            raise ValueError("If given, length of x along axis must be the "
                             "same as y.")
    if N % 2 == 0:
        val = 0.0
        result = 0.0
        slice1 = (slice(None),)*nd
        slice2 = (slice(None),)*nd
        if even not in ['avg', 'last', 'first']:
            raise ValueError("Parameter 'even' must be "
                             "'avg', 'last', or 'first'.")
        # Compute using Simpson's rule on first intervals
        if even in ['avg', 'first']:
            slice1 = tupleset(slice1, axis, -1)
            slice2 = tupleset(slice2, axis, -2)
            if x is not None:
                last_dx = x[slice1] - x[slice2]
            val += 0.5*last_dx*(y[slice1]+y[slice2])
            result = _basic_simps(y, 0, N-3, x, dx, axis)
        # Compute using Simpson's rule on last set of intervals
        if even in ['avg', 'last']:
            slice1 = tupleset(slice1, axis, 0)
            slice2 = tupleset(slice2, axis, 1)
            if x is not None:
                first_dx = x[tuple(slice2)] - x[tuple(slice1)]
            val += 0.5*first_dx*(y[slice2]+y[slice1])
            result += _basic_simps(y, 1, N-2, x, dx, axis)
        if even == 'avg':
            val /= 2.0
            result /= 2.0
        result = result + val
    else:
        result = _basic_simps(y, 0, N-2, x, dx, axis)
    if returnshape:
        x = x.reshape(saveshape)
    return result


def romb(y, dx=1.0, axis=-1, show=False):
    """
    Romberg integration using samples of a function.

    Parameters
    ----------
    y : array_like
        A vector of ``2**k + 1`` equally-spaced samples of a function.
    dx : float, optional
        The sample spacing. Default is 1.
    axis : int, optional
        The axis along which to integrate. Default is -1 (last axis).
    show : bool, optional
        When `y` is a single 1-D array, then if this argument is True
        print the table showing Richardson extrapolation from the
        samples. Default is False.

    Returns
    -------
    romb : ndarray
        The integrated result for `axis`.

    See also
    --------
    quad : adaptive quadrature using QUADPACK
    romberg : adaptive Romberg quadrature
    quadrature : adaptive Gaussian quadrature
    fixed_quad : fixed-order Gaussian quadrature
    dblquad : double integrals
    tplquad : triple integrals
    simps : integrators for sampled data
    cumtrapz : cumulative integration for sampled data
    ode : ODE integrators
    odeint : ODE integrators

    Examples
    --------
    >>> from scipy import integrate
    >>> x = np.arange(10, 14.25, 0.25)
    >>> y = np.arange(3, 12)

    >>> integrate.romb(y)
    56.0

    >>> y = np.sin(np.power(x, 2.5))
    >>> integrate.romb(y)
    -0.742561336672229

    >>> integrate.romb(y, show=True)
    Richardson Extrapolation Table for Romberg Integration
    ====================================================================
    -0.81576
    4.63862  6.45674
    -1.10581 -3.02062 -3.65245
    -2.57379 -3.06311 -3.06595 -3.05664
    -1.34093 -0.92997 -0.78776 -0.75160 -0.74256
    ====================================================================
    -0.742561336672229
    """
    y = np.asarray(y)
    nd = len(y.shape)
    Nsamps = y.shape[axis]
    Ninterv = Nsamps-1
    n = 1
    k = 0
    while n < Ninterv:
        n <<= 1
        k += 1
    if n != Ninterv:
        raise ValueError("Number of samples must be one plus a "
                         "non-negative power of 2.")

    R = {}
    slice_all = (slice(None),) * nd
    slice0 = tupleset(slice_all, axis, 0)
    slicem1 = tupleset(slice_all, axis, -1)
    h = Ninterv * np.asarray(dx, dtype=float)
    R[(0, 0)] = (y[slice0] + y[slicem1])/2.0*h
    slice_R = slice_all
    start = stop = step = Ninterv
    for i in range(1, k+1):
        start >>= 1
        slice_R = tupleset(slice_R, axis, slice(start, stop, step))
        step >>= 1
        R[(i, 0)] = 0.5*(R[(i-1, 0)] + h*y[slice_R].sum(axis=axis))
        for j in range(1, i+1):
            prev = R[(i, j-1)]
            R[(i, j)] = prev + (prev-R[(i-1, j-1)]) / ((1 << (2*j))-1)
        h /= 2.0

    if show:
        if not np.isscalar(R[(0, 0)]):
            print("*** Printing table only supported for integrals" +
                  " of a single data set.")
        else:
            try:
                precis = show[0]
            except (TypeError, IndexError):
                precis = 5
            try:
                width = show[1]
            except (TypeError, IndexError):
                width = 8
            formstr = "%%%d.%df" % (width, precis)

            title = "Richardson Extrapolation Table for Romberg Integration"
            print("", title.center(68), "=" * 68, sep="\n", end="\n")
            for i in range(k+1):
                for j in range(i+1):
                    print(formstr % R[(i, j)], end=" ")
                print()
            print("=" * 68)
            print()

    return R[(k, k)]

# Romberg quadratures for numeric integration.
#
# Written by Scott M. Ransom <ransom@cfa.harvard.edu>
# last revision: 14 Nov 98
#
# Cosmetic changes by Konrad Hinsen <hinsen@cnrs-orleans.fr>
# last revision: 1999-7-21
#
# Adapted to SciPy by Travis Oliphant <oliphant.travis@ieee.org>
# last revision: Dec 2001


def _difftrap(function, interval, numtraps):
    """
    Perform part of the trapezoidal rule to integrate a function.
    Assume that we had called difftrap with all lower powers-of-2
    starting with 1. Calling difftrap only returns the summation
    of the new ordinates. It does _not_ multiply by the width
    of the trapezoids. This must be performed by the caller.
        'function' is the function to evaluate (must accept vector arguments).
        'interval' is a sequence with lower and upper limits
                   of integration.
        'numtraps' is the number of trapezoids to use (must be a
                   power-of-2).
    """
    if numtraps <= 0:
        raise ValueError("numtraps must be > 0 in difftrap().")
    elif numtraps == 1:
        return 0.5*(function(interval[0])+function(interval[1]))
    else:
        numtosum = numtraps/2
        h = float(interval[1]-interval[0])/numtosum
        lox = interval[0] + 0.5 * h
        points = lox + h * np.arange(numtosum)
        s = np.sum(function(points), axis=0)
        return s


def _romberg_diff(b, c, k):
    """
    Compute the differences for the Romberg quadrature corrections.
    See Forman Acton's "Real Computing Made Real," p 143.
    """
    tmp = 4.0**k
    return (tmp * c - b)/(tmp - 1.0)


def _printresmat(function, interval, resmat):
    # Print the Romberg result matrix.
    i = j = 0
    print('Romberg integration of', repr(function), end=' ')
    print('from', interval)
    print('')
    print('%6s %9s %9s' % ('Steps', 'StepSize', 'Results'))
    for i in range(len(resmat)):
        print('%6d %9f' % (2**i, (interval[1]-interval[0])/(2.**i)), end=' ')
        for j in range(i+1):
            print('%9f' % (resmat[i][j]), end=' ')
        print('')
    print('')
    print('The final result is', resmat[i][j], end=' ')
    print('after', 2**(len(resmat)-1)+1, 'function evaluations.')


def romberg(function, a, b, args=(), tol=1.48e-8, rtol=1.48e-8, show=False,
            divmax=10, vec_func=False):
    """
    Romberg integration of a callable function or method.

    Returns the integral of `function` (a function of one variable)
    over the interval (`a`, `b`).

    If `show` is 1, the triangular array of the intermediate results
    will be printed. If `vec_func` is True (default is False), then
    `function` is assumed to support vector arguments.

    Parameters
    ----------
    function : callable
        Function to be integrated.
    a : float
        Lower limit of integration.
    b : float
        Upper limit of integration.

    Returns
    -------
    results  : float
        Result of the integration.

    Other Parameters
    ----------------
    args : tuple, optional
        Extra arguments to pass to function. Each element of `args` will
        be passed as a single argument to `func`. Default is to pass no
        extra arguments.
    tol, rtol : float, optional
        The desired absolute and relative tolerances. Defaults are 1.48e-8.
    show : bool, optional
        Whether to print the results. Default is False.
    divmax : int, optional
        Maximum order of extrapolation. Default is 10.
    vec_func : bool, optional
        Whether `func` handles arrays as arguments (i.e., whether it is a
        "vector" function). Default is False.

    See Also
    --------
    fixed_quad : Fixed-order Gaussian quadrature.
    quad : Adaptive quadrature using QUADPACK.
    dblquad : Double integrals.
    tplquad : Triple integrals.
    romb : Integrators for sampled data.
    simps : Integrators for sampled data.
    cumtrapz : Cumulative integration for sampled data.
    ode : ODE integrator.
    odeint : ODE integrator.

    References
    ----------
    .. [1] 'Romberg's method' https://en.wikipedia.org/wiki/Romberg%27s_method

    Examples
    --------
    Integrate a gaussian from 0 to 1 and compare to the error function.

    >>> from scipy import integrate
    >>> from scipy.special import erf
    >>> gaussian = lambda x: 1/np.sqrt(np.pi) * np.exp(-x**2)
    >>> result = integrate.romberg(gaussian, 0, 1, show=True)
    Romberg integration of <function vfunc at ...> from [0, 1]

    ::

       Steps  StepSize  Results
           1  1.000000  0.385872
           2  0.500000  0.412631  0.421551
           4  0.250000  0.419184  0.421368  0.421356
           8  0.125000  0.420810  0.421352  0.421350  0.421350
          16  0.062500  0.421215  0.421350  0.421350  0.421350  0.421350
          32  0.031250  0.421317  0.421350  0.421350  0.421350  0.421350  0.421350

    The final result is 0.421350396475 after 33 function evaluations.

    >>> print("%g %g" % (2*result, erf(1)))
    0.842701 0.842701

    """
    if np.isinf(a) or np.isinf(b):
        raise ValueError("Romberg integration only available "
                         "for finite limits.")
    vfunc = vectorize1(function, args, vec_func=vec_func)
    n = 1
    interval = [a, b]
    intrange = b - a
    ordsum = _difftrap(vfunc, interval, n)
    result = intrange * ordsum
    resmat = [[result]]
    err = np.inf
    last_row = resmat[0]
    for i in range(1, divmax+1):
        n *= 2
        ordsum += _difftrap(vfunc, interval, n)
        row = [intrange * ordsum / n]
        for k in range(i):
            row.append(_romberg_diff(last_row[k], row[k], k+1))
        result = row[i]
        lastresult = last_row[i-1]
        if show:
            resmat.append(row)
        err = abs(result - lastresult)
        if err < tol or err < rtol * abs(result):
            break
        last_row = row
    else:
        warnings.warn(
            "divmax (%d) exceeded. Latest difference = %e" % (divmax, err),
            AccuracyWarning)

    if show:
        _printresmat(vfunc, interval, resmat)
    return result


# Coefficients for Newton-Cotes quadrature
#
# These are the points being used
#  to construct the local interpolating polynomial
#  a are the weights for Newton-Cotes integration
#  B is the error coefficient.
#  error in these coefficients grows as N gets larger.
#  or as samples are closer and closer together

# You can use maxima to find these rational coefficients
#  for equally spaced data using the commands
#  a(i,N) := integrate(product(r-j,j,0,i-1) * product(r-j,j,i+1,N),r,0,N) / ((N-i)! * i!) * (-1)^(N-i);
#  Be(N) := N^(N+2)/(N+2)! * (N/(N+3) - sum((i/N)^(N+2)*a(i,N),i,0,N));
#  Bo(N) := N^(N+1)/(N+1)! * (N/(N+2) - sum((i/N)^(N+1)*a(i,N),i,0,N));
#  B(N) := (if (mod(N,2)=0) then Be(N) else Bo(N));
#
# pre-computed for equally-spaced weights
#
# num_a, den_a, int_a, num_B, den_B = _builtincoeffs[N]
#
#  a = num_a*array(int_a)/den_a
#  B = num_B*1.0 / den_B
#
#  integrate(f(x),x,x_0,x_N) = dx*sum(a*f(x_i)) + B*(dx)^(2k+3) f^(2k+2)(x*)
#    where k = N // 2
#
_builtincoeffs = {
    1: (1,2,[1,1],-1,12),
    2: (1,3,[1,4,1],-1,90),
    3: (3,8,[1,3,3,1],-3,80),
    4: (2,45,[7,32,12,32,7],-8,945),
    5: (5,288,[19,75,50,50,75,19],-275,12096),
    6: (1,140,[41,216,27,272,27,216,41],-9,1400),
    7: (7,17280,[751,3577,1323,2989,2989,1323,3577,751],-8183,518400),
    8: (4,14175,[989,5888,-928,10496,-4540,10496,-928,5888,989],
        -2368,467775),
    9: (9,89600,[2857,15741,1080,19344,5778,5778,19344,1080,
                 15741,2857], -4671, 394240),
    10: (5,299376,[16067,106300,-48525,272400,-260550,427368,
                   -260550,272400,-48525,106300,16067],
         -673175, 163459296),
    11: (11,87091200,[2171465,13486539,-3237113, 25226685,-9595542,
                      15493566,15493566,-9595542,25226685,-3237113,
                      13486539,2171465], -2224234463, 237758976000),
    12: (1, 5255250, [1364651,9903168,-7587864,35725120,-51491295,
                      87516288,-87797136,87516288,-51491295,35725120,
                      -7587864,9903168,1364651], -3012, 875875),
    13: (13, 402361344000,[8181904909, 56280729661, -31268252574,
                           156074417954,-151659573325,206683437987,
                           -43111992612,-43111992612,206683437987,
                           -151659573325,156074417954,-31268252574,
                           56280729661,8181904909], -2639651053,
         344881152000),
    14: (7, 2501928000, [90241897,710986864,-770720657,3501442784,
                         -6625093363,12630121616,-16802270373,19534438464,
                         -16802270373,12630121616,-6625093363,3501442784,
                         -770720657,710986864,90241897], -3740727473,
         1275983280000)
    }


def newton_cotes(rn, equal=0):
    r"""
    Return weights and error coefficient for Newton-Cotes integration.

    Suppose we have (N+1) samples of f at the positions
    x_0, x_1, ..., x_N. Then an N-point Newton-Cotes formula for the
    integral between x_0 and x_N is:

    :math:`\int_{x_0}^{x_N} f(x)dx = \Delta x \sum_{i=0}^{N} a_i f(x_i)
    + B_N (\Delta x)^{N+2} f^{N+1} (\xi)`

    where :math:`\xi \in [x_0,x_N]`
    and :math:`\Delta x = \frac{x_N-x_0}{N}` is the average samples spacing.

    If the samples are equally-spaced and N is even, then the error
    term is :math:`B_N (\Delta x)^{N+3} f^{N+2}(\xi)`.

    Parameters
    ----------
    rn : int
        The integer order for equally-spaced data or the relative positions of
        the samples with the first sample at 0 and the last at N, where N+1 is
        the length of `rn`. N is the order of the Newton-Cotes integration.
    equal : int, optional
        Set to 1 to enforce equally spaced data.

    Returns
    -------
    an : ndarray
        1-D array of weights to apply to the function at the provided sample
        positions.
    B : float
        Error coefficient.

    Examples
    --------
    Compute the integral of sin(x) in [0, :math:`\pi`]:

    >>> from scipy.integrate import newton_cotes
    >>> def f(x):
    ...     return np.sin(x)
    >>> a = 0
    >>> b = np.pi
    >>> exact = 2
    >>> for N in [2, 4, 6, 8, 10]:
    ...     x = np.linspace(a, b, N + 1)
    ...     an, B = newton_cotes(N, 1)
    ...     dx = (b - a) / N
    ...     quad = dx * np.sum(an * f(x))
    ...     error = abs(quad - exact)
    ...     print('{:2d}  {:10.9f}  {:.5e}'.format(N, quad, error))
    ...
     2   2.094395102   9.43951e-02
     4   1.998570732   1.42927e-03
     6   2.000017814   1.78136e-05
     8   1.999999835   1.64725e-07
    10   2.000000001   1.14677e-09

    Notes
    -----
    Normally, the Newton-Cotes rules are used on smaller integration
    regions and a composite rule is used to return the total integral.

    """
    try:
        N = len(rn)-1
        if equal:
            rn = np.arange(N+1)
        elif np.all(np.diff(rn) == 1):
            equal = 1
    except Exception:
        N = rn
        rn = np.arange(N+1)
        equal = 1

    if equal and N in _builtincoeffs:
        na, da, vi, nb, db = _builtincoeffs[N]
        an = na * np.array(vi, dtype=float) / da
        return an, float(nb)/db

    if (rn[0] != 0) or (rn[-1] != N):
        raise ValueError("The sample positions must start at 0"
                         " and end at N")
    yi = rn / float(N)
    ti = 2 * yi - 1
    nvec = np.arange(N+1)
    C = ti ** nvec[:, np.newaxis]
    Cinv = np.linalg.inv(C)
    # improve precision of result
    for i in range(2):
        Cinv = 2*Cinv - Cinv.dot(C).dot(Cinv)
    vec = 2.0 / (nvec[::2]+1)
    ai = Cinv[:, ::2].dot(vec) * (N / 2.)

    if (N % 2 == 0) and equal:
        BN = N/(N+3.)
        power = N+2
    else:
        BN = N/(N+2.)
        power = N+1

    BN = BN - np.dot(yi**power, ai)
    p1 = power+1
    fac = power*math.log(N) - gammaln(p1)
    fac = math.exp(fac)
    return ai, BN*fac
